Docs/Python/密码输入显示为.html
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<!DOCTYPE html>
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<title>密码输入显示为*</title>
<style>
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margin: 0;
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h1{font-size:30px}h2{font-size:24px}h3{font-size:18px}h4{font-size:14px}
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margin: 0;
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margin-bottom: 16px;
border-collapse: collapse;
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</head>
<body>
<div class="note-container">
<h1 class="title" id="leanote-title">密码输入显示为*</h1>
<div class="content-html" id="leanote-content"><pre id="leanote_ace_1512008784242_0" class="brush:python ace-tomorrow">import msvcrt, sys, os
print('password: ', end='', flush=True)
li = []
while 1:
ch = msvcrt.getch()
#回车
if ch == b'\r':
msvcrt.putch(b'\n')
print('输入的密码是:%s' % b''.join(li).decode())
break
#退格
elif ch == b'\x08':
if li:
li.pop()
msvcrt.putch(b'\b')
msvcrt.putch(b' ')
msvcrt.putch(b'\b')
#Esc
elif ch == b'\x1b':
break
else:
li.append(ch)
msvcrt.putch(b'*')
os.system('pause')</pre><p><br data-mce-bogus="1"></p><pre id="leanote_ace_1512008880671_0" class="brush:python ace-tomorrow">def pwd_input(msg = ''):
import msvcrt, sys
if msg != '':
sys.stdout.write(msg)
chars = []
while True:
newChar = msvcrt.getch()
if newChar in '\3\r\n': # 如果是换行Ctrl+C则输入结束
print ''
if newChar in '\3': # 如果是Ctrl+C则将输入清空返回空字符串
chars = []
break
elif newChar == '\b': # 如果是退格,则删除末尾一位
if chars:
del chars[-1]
sys.stdout.write('\b \b') # 左移一位,用空格抹掉星号,再退格
else:
chars.append(newChar)
sys.stdout.write('*') # 显示为星号
return ''.join(chars) </pre><p><br data-mce-bogus="1"></p></div>
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